Solve the simultaneous equations: y=x^2+4x-2, y=x+2

Equations: 1). y=x^2+4x-2 2.)y=x+2 x+2=x^2+4x-2 First put equation 1 in equation 2 0=x^2+3x-4 Make one side of the equation equal to 0 0=(x+4)(x-1) Factorise the equations Equations 3).x+4=0 4). x-1=0 One or both of the brackets in the factorised form must equal 0 for the whole equation to be equal to 0. x=-4 x=1 Solve equations 3 and 4 Remember to find y by substituting in values of x into equation 2.) to fully solve the equations y=x+2 y=-2 y=3 Answer: When x=-4 y=-2, when x=1 y=3

Answered by Phoebe A. Maths tutor

2793 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations for x and y : 2x - y = 12; x + 3y = 20


solve the inequality 5x + 3> 3x - 6


Given that F(x) = X^2 - 10X + 17. Write F(x) in the form of (x+a)^2 + b = 0, where a, & b are constants.


Solve the simultaneous equations: x^2+y^2=36 ; x=2y+6


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences