Solve x^2+4x-5=0 by completing the square.

x^2+4x-5=0(x+2)^2-(2)^2-5=0subtract 2^2 as (x+2)^2 = x^2+4x+4 when we want x^2+4x(x+2)^2-4-5=0(x+2)^2-9=0(x+2)^2=9square root both sidesx+2=+/-3x=-2+/-3x=-2+3 or x=-2-3x=1 or x=-5

Answered by Evie M. Maths tutor

9513 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the median, upper and lower quartiles of these numbers: 160, 390, 169, 175, 125, 420, 171, 250, 210, 258, 186, 243


Solve algebraically for a and b: 6a+b=16, 5a-2b=19


Rationalise the following: { 5 } / { 3 - sqrt(2) }


The two points (4,9) and (2,3) are on line A. A second line, line B is perpendicular to line A and goes through the point (2,3). What is the equation of line B?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences