Integrate the function f(x) = ax^2 + bx + c over the interval [0,1], where a, b and c are constants.

Firstly remember that d/dx(x^n) = nx^(n-1). And so the antiderivative, or integral of x^n, i.e. \int(x^n) = x^(n+1)/(n+1) + C (where C is the integration constant). When integrating with limits, i.e. when we define an interval that we're integrating over, we do not have to worry about the constant C, and so for example: \int(x^3) over [0,1] will be x^4/4 (x=1 - x=0), i.e. = 1^4/4 - 0^4/4 = 1/4.

Hence, for our given function f(x), \int(f(x)) over [0,1] will be ax^3/3 + bx^2/2 + cx/1 (x=1 - x=0) = a/3 + b/2 + c.

AA
Answered by Anvarbek A. Maths tutor

3865 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Prove: (1-cos(2A))/sin(2A) = tan(A)


If y = 1/(x^2) + 4x, find dy/dx


What is the intergral of 6.x^2 + 2/x^2 + 5 with respect to x?


Can you explain the product rule when differentiating?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences