Sketch the curve y=4-(x+3)^2, showing the points where the curve crosses the x-axis and any minimum or maximum points.

This equation rearranges to give -y=(x+3)^2-4, which is very similar to our curve y=(x+3)^2-4 from before. In fact, replacing y with -y in an equation is equivalent to reflecting the curve through the x-axis. We then take the points (-5,0), (-1,0) and (-3,-4) from before and replace y with -y, giving (-5,0), (-1,0) and (-3,4). We have found where the new curve crosses the x-axis and its minimum/maximum. The graph is an inverted u-shape since we have a -x^2 in the equation so (-3,4) is a maximum point.

JI
Answered by Jonny I. Maths tutor

3397 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you complete the square for the question x^2 + 6x - 10 ?


A bag with 750 balls is comprised of 300 red, 200 blue and 250 green. What is the probability of three green balls being in succession, providing the ball is put back between each turn.


From June 2015 Edexcel paper: Solve 7x + 8 = 2x – 3


Frank, Mary and Seth shared some sweets in the ratio 4:5:7. Seth got 18 more sweets than Frank. How many sweets were shared in total?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences