The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).

When we find dy/dx we find the gradient of the curve at (3,1). Start by differentiating the left hand side (LHS) like so.. (whiteboard). Remember every time we differentiate a y value we multiply by dy/dx. This is because we differentiate y with respect to y and then multiply by dy/dx to get y differentiated with respect to x (by the chain rule). We now differentiate the RHS... (whiteboard) Now collect the dy/dx terms on the LHS and the other terms on the RHS like so... (whiteboard) Now sub in x=3 and y=1 and we obtain dy/dx=1/7.

CR
Answered by Caitlin R. Maths tutor

5268 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I integrate sin^2 (x) dx?


Solve $\color{orange}{a}x^2 - \color{blue}{b}x + \color{green}{c} = 0$


Find the general solution to the differential equation '' (x^2 + 3x - 1) dy/dx = (2x + 3)y ''


For rectangles of area 100 m^2 what is the perimeter of the rectangle with the smallest perimeter?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning