The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).

When we find dy/dx we find the gradient of the curve at (3,1). Start by differentiating the left hand side (LHS) like so.. (whiteboard). Remember every time we differentiate a y value we multiply by dy/dx. This is because we differentiate y with respect to y and then multiply by dy/dx to get y differentiated with respect to x (by the chain rule). We now differentiate the RHS... (whiteboard) Now collect the dy/dx terms on the LHS and the other terms on the RHS like so... (whiteboard) Now sub in x=3 and y=1 and we obtain dy/dx=1/7.

CR
Answered by Caitlin R. Maths tutor

5462 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that x = 4sin(2y + 6), Find dy/dx in terms of x


Find the derivative of y = 3x^4 - 10x^2+7x


Prove by induction that, for n ∈ Z⁺ , [3 , -2 ; 2 , -1]ⁿ = [2n+1 , -2n ; 2n , 1-2n]


How would I differentiate a function of the form y=(f(x))^n?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning