Factorise: 6x^2-3x-3=0

Since the equation shows a 6x^2, we know that in the brackets we must have either: (2x+a)(3x+b) or (6x+a)(x+b) However we know the last two numbers must multiply to make -3, hence a and b must be +1 and -3 respectively and so we know the second solution is the one to use. This leads us to the final step --> the inner number must be the added product of the x terms and a and b. This means that to get -3x we need to place the numbers as follows: (6x+3)(x-1) This is because (6x)(-1)=-6x and (x)(3)=3x and so the sum of these numbers gives us the middle term.

Answered by William P. Maths tutor

3031 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 11 pens in a box, 8 are black, 3 are red. Two pens are taken out at random without replacement. What is the probability the pens are the same colour?


HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts


The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.


Fully simplify: (y^2 x y^5) / y^3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences