25cm3 of NaOH (2M) were titrated with 1.25M H2SO4. Write down the balanced reaction equation. Calculate the number of moles of NaOH used in the titration and hence deduce the volume of sulfuric acid used in the titration. Give your answer in dm3.
2NaOH + H2SO4 -> 2H2O + Na2SO4. moles = concentration x volume. #moles NaOH = 2M x (25/1000)dm3 = 0.05 mol. The reaction equations shows the ratio of alkali to acid is 2:1. The number of moles of H2SO4 required for neutralisation is half of the number of moles of NaOH. #mole H2SO4 = 0.05/2 = 0.025 mol. volume of H2SO4 = moles / concentration = 0.025/1.25 = 0.02 dm3.
TW
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