Solve the equation |3x + 4| = |3x - 11|

Here we have an equation involving absolute values. As a general rule |a| = +a and |a| = -a. We can apply that to our RHS. In the first case we get that 3x + 4 = 3x - 11, however after we subtract 3x from both sides we are left with 4 = -11, which is obviously false. Therefore, we conclude that there are no solutions for |a| = +a and we move on to |a| = -a. Applying our formula again we have 3x + 4 = - (3x - 11) or 3x + 4 = - 3x + 11. Rearranging we get that 6x = 7 or that x = 7/6.

VB
Answered by Viktoria B. Maths tutor

8222 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the simultaneous equations x – 2y = 1 and x^2 + y^2 = 29.


A curve has parametric equations: x=(t-1)^3 and y= 3t - 8/(t^2). Find dy/dx in terms of t. Then find the equation of the normal at the point on the curve where t=2.


Integrate (x^2)(e^x) with respect to x


if a^x= b^y = (ab)^(xy) prove that x+y =1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning