An electrical heater supplies 500J of heat energy to a copper cylinder of mass 32.4g Find the increase in temperature of the cylinder. (Specific heat capacity of copper = 385 J*kg^-1*Celsius^-1
The temperature of a body of mass m and specific heat capacity c rises by change in temperature (delta)T when an amount of heat Q is added to it (Q = mc(delta)T). From the equation we see that the change in temperature is simply equal to the heat divided by the mass times the specific heat capacity of copper ((delta)T = Q / m*c). Now we can just plug in the numbers to find the answer. (Note that the mass is not given in SI units and we have to convert it 32.4g = 0.0324kg). From here follows that the increase in temperature is equal to 500 / 0.0324 * 385 or 40.0834, which we can round to 40.1 degrees Celsius.
VB
Related Physics A Level answers
All answers ▸What is the minimum height of a hill, so a ball of mass m falling from it can go through a loop of radius R?
A ball of mass 0.7 kg strikes the wall at an angle of 90 degrees with speed 72 km/h. Consider that the bounce lasts for 0.1 s and is perfectly elastic. What is the magnitude of the average reaction force from the wall that acts on the ball?
An aeroplane lands on the runway with a velocity of 50 m/s and decelerates at 10 m/s^2 to a velocity of 20 m/s. Calculate the distance travelled on the runway.
A ball is kicked off a cliff at a height of 20m above ground and an angle of 30 degree from the horizontal, it follows projectile motion and lands after a time t. Its velocity at the maximum height it reaches is 20m/s, how long does it take it to land?