When 0.81 m of a wire with cross-sectional area of 3.1*10^-11 m^2 is connected across a 2 V battery a current of 1.6 A flows in the wire. Find the resistivity of the material of the wire.

The resistance in the wire is given by the resistivity of the material by the lenght and divided by the cross-sectional area (R = pL/A). From here we can rearrange and have p = RA/L. However, we also know that R = V/I, and thus, our final formula becomes p = VA / IL. Plugging in the numbers we get p = 23.110^-11 / 1.60.81, which is equal to 4.7839510^-11, or rounding, 4.8*10^-11 Ohm-meters.

Answered by Viktoria B. Physics tutor

5005 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What are Newton's three laws?


Explain the gaps within an absorption spectrum and where this may commonly occur in the universe


How can we explain the standing waves on a string?


What is the angular velocity of a person standing on the surface of the earth. Give your answer in radians per second


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences