What are the half equations representing the changes of Pb2+ and Br- in the electrolysis of lead bromide?

Pb2+ + 2e- -> Pb 2Br- -> Br2 + 2e- Lead ions undergo reduction (gain of electrons) at the negative electrode to form solid lead. Bromide ions undergo oxidation (loss of electrons) at the positive electrode to form bromine gas. Note two electrons are required due to the valency of lead being 2+ and hence 2x Br- are needed.