A* grade question: ((2x+3)/(x-4))-((2x-8)/(2x+1))=1 solve for X

Multiply whole equation by x-4 and then 2x+1 (would do this one step at a time but must conserve space here):

(2x+3)(2x+1)-(2x-8)(x-4)=(x-4)(2x+1)

Expand brackets:

(4x^2+8x+3)-(2x^2-16x+32)= 2x^2-7x-4

Do the subtraction: 2x^2+24x-29=2x^2-7x-4

Minus 2x^2 from both sides:

24x-29=-7x-4

Bring Xs to left hand side and integers to right hand side of equals sign:

31x=25

X=25/31

Answered by Becky L. Maths tutor

3812 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solving quadratic equations using the factorisation method.


Bob and Bill have 50 sweets to share in the ratio 4:6 respectively. how many do they each get?


a) You area told that y is proportional to x2 and that when y = 75, x = 5. Find a formula for y in terms of x. y = x b) Find the value of y when x = 3. c) Find the value of x when y = 1200.


solve (2x+3)/(x-4) - (2x-8)/(2x+1) = 1 leave answer in fraction form


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences