find dy/dx of the equation y=ln(x)2x^2

Here it is necessary to use the chain rule to solve the derivative. If we equate our equation in terms of the following notation: ln(x)='u'and 2x^2='v' and use the chain rule formula dy/dx=udv/dx+vdu/dx we can solve the derivative:

= lnx(4x)+(2x^2)(1/x) = 4xlnx+2x

Answered by Pierce G. Maths tutor

3550 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate xsin(x) with respect to x


Find the derivative of f(x) = 2xe^x


Prove by induction that the nth triangle number is given by n(n+1)/2


Find the derivative of y = 3x^4 - 10x^2+7x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences