In a titration, 50 cm3 of sodium hydroxide with a concentration of 0.3 mol/dm3 was neutralised by 60 cm3 of hydrochloric acid. Calculate the concentration of the hydrochloric acid in mol/dm3.

HCl + NaOH = NaCl + H2O. Moles = volume (dm3) x concentration (mol/dm3). Moles of NaOH: volume x concentration = (50/1000) x 0.3 = 0.015 moles. 1 to 1 ratio of HCl to NaOH, so there were 0.015 moles of HCl. Concentration of HCl: moles/volume = 0.015/(60/1000) = 0.25 mol/dm3.

Answered by Aarushi V. Chemistry tutor

24412 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Explain the difference between an unsaturated and saturated compound.


Show the covalent bonding in terms of electrons in their outer shell for a molecule of Carbon Dioxide


Why is Copper used in cooking equipment and wiring?


Describe and explain the properties of graphene


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences