Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12
Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4x=12-4, 4x=8, giving the answer x=2. Substitute this in to equation (1) to solve for y. y=(2)/2 + 2, giving y=3.
JB
Related Maths GCSE answers
All answers ▸A right-angled triangle has one angle size 60 degrees, and hypotenuse of length 32cm. Calculate the length of the side opposite the 60 degree angle, to 3sf.
Find x when: (2^x)(e^(3x+1))=10. Give your answer in the form (a + ln(b)) / (c + ln(d)) , where a,b,c,d are integers.
Factorise and solve 3x^2-x-10=0
Solve 2x^2+7x+6=0