solve the simultaneous equations , 5a+2b=23 & 9a-2b=19, algebraically.
find sum of both equations: 14a=42, therefore a=3, substitute 'a' into an equation: (5x3)+2b=23, therefore 2b=8, therfore b=4
RP
find sum of both equations: 14a=42, therefore a=3, substitute 'a' into an equation: (5x3)+2b=23, therefore 2b=8, therfore b=4