Differentiate y=4x^2+3x+9

Use the rule of "bringing down the power" and then reducing the power by 1. Start with 4x^2. "Bring down" the 2 to make (4)(2)x^2, then reduce the power by 1 to make 8x. Now repeat this with 3x (you can imagine this as 3x^1 if this is easier). Bring down the 1 to make (3)(1)x^1 and then reduce the power by 1 to make 3x^0 which is 3. 9 cannot be differentiated , so we just get 0. Overall, this gives us dy/dx = 8x + 3

Answered by Tarryn R. Maths tutor

5494 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I differentiate an algebraic expression? (e.g. y=3x^4 - 8x^3 - 3) [the ^ represents x being raised to a power]


Differentiate ln(x^3 +2) with respect to x


Given y = 2x(x^2 – 1)^5, show that dy/dx = g(x)(x^2 – 1)^4 where g(x) is a function to be determined.


Integral of 1/(x^3 + 2x^2 -x - 2)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences