Derive Keplers 3rd law

Equate gravitational force (GMm/r^2) to centripetal force (mv^2/r). Rearrange to get v^2=GM/r. Due to the approximated circular orbit v=2pir/T so v^2=4pi^2r^2/T^2. Therefore GM/r=4pi^2r^2/T^2. Rearranging gives GM=4pi^2r^3/T^2. Rearranging futher gets T^2=(4pi^2/GM)r^3. Hence T^2 is proportional to r^3.

MS
Answered by Michael S. Physics tutor

4412 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

On the line of centres between the Earth and the Moon, there is a point where the net gravitational force is zero. Given that the distance between the two is 385,000 km, and that the Earth has a mass 81x that of the Moon, how far is this point from Earth?


Describe the energy changes in the 4 stages of a bungee jump - at the top, in freefall, when the cord is stretching and at the bottom


What is the difference between a scalar and a vector quantity?


How should I structure my experiment report?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning