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The curve C has the equation (x^2)+4xy-8(y^2)+27=0. Find dy/dx in terms of x and y.
dy/dx= (x+2y)/(8y-2x)
Answered by Emily O. •
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a typical question would be a setof parametric equations y(t) and x(t), asking you to find dy/dx and then the tangent/normal to the curve at a certain point (ie t = 2)
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