When a toothbrush is charging, p.d. across the primary coil is 230 V, p.d. across the secondary coil is 7.2 V. The primary coil in the charging base has 575 turns of wire on its coil. Find the number of turns on the secondary coil inside the toothbrush.

This question is on transformers. This is clear because there is a primary and secondary coil and a different voltage between the 2 coils. Transformers induce a changing voltage in a coil. The known equation for finding the number of coils is: primary voltage / secondary voltage = turns on primary / turns on secondary.

Therefore numbers can be subbed in: 230/7.2=575/turns on secondary. This is rearranged to get 18.

JT
Answered by Jayani T. Physics tutor

6015 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is the Doppler effect?


Outline the structure of the alpha and beta particle and give their overall charge and a material which it cannot pass through.


What is the mass of an object travelling at 15 m/s with a kinetic energy of 100 J?


A lamp has a rating of 18V 9W. How much energy is transferred to the bulb in 5 minutes? Calculate the current through it when connected to a 18V supply.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning