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Given that y=4x^3-(5/x^2) what is dy/dx in it's simplest form?
y = 4x^3-5x^-2 dy/dx = 12x^2+10x^-3
Answered by Trishul P. •
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Given a second order Differential Equation, how does one derive the Characteristic equation where one can evaluate and find the constants
x^3 + 3x^2 + 2x + 12
Find dy/dx for y=5x^3−2x^2+7x−15
7x+5y-3z =16, 3x-5y+2z=-8, 5x+3y-7z=0. Solve for x,y and z.
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