Tim stretches by leaning against a pole that is 1.5 metres tall and at a right angle to the floor. Tim is standing 0.5 metres away from the pole, how tall is Tim; leaving your answer in terms of metres? (2.d.p)

This can be solved using Pythagoras. We know that the pole is 90 degrees to the floor so the height of the pole is the opposite side. The distance between Tim and the pole is therefore the adjacent and hence we can find the hypotenuse. Using the formula sqrt(a^2+b^2)=c^2 we can substitute in for a=1500cm, b=500cm. This therefore gives us c=1581.14cm. converted back into metres, c=1.58 metres.

Answered by Morgan S. Maths tutor

2724 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve simultaneously, x+y=2 and 4y^2-x^2=11


You are told that a straight line runs through 2 points: (1,1) and (2,3). What is the equation of the line?


Determine the coordinates of the intersection point(s) between the line y = x^2 + 4x - 8 and y = - 2x - 17


How would you simplify this: ((4x+1)/4)+((1-3x)/3)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences