Answers>Maths>A Level>Article

Solve the simultaneous equations: y-2x-4 = 0 (1) , 4x^2 +y^2 + 20x = 0 (2)

Re-arrange (1) : y = 2x + 4 Square both sides: y^2 = 4x^2 + 16 Substitute (1) into (2) and simplify: 2x^2 + 9x + 4 = 0 Factorise the equation: (2x+1)(x+4) = 0 Solve for x: x = -1/2 and x = -4 Substitute these x values in (1) to find corresponding y values for each x.

Answered by Giorgos A. • Maths tutor

10163 Views

See similar Maths A Level tutors

Solve the simultaneous equations: y-2x-4 = 0 (1) , 4x^2 +y^2 + 20x = 0 (2)

Related Maths A Level answers

What does it mean when I get a negative value when I do a definite integral?

Express as a single logarithm 2 loga 6 loga 3 [2 marks]

The equation 5x sqaured + px + q , where p and q are constants, has roots α and α + 4. (a) Show that p squared = 20q +400.

Find the integral of log|x| by integration by parts