How would you solve a quadratic equation (e.g. x^2-8x+15=0)?

There are two ways to solve the equation. One is to simply factorise it and the other is to use the formula provided in the formula booklet. The second method is probably easier when there isn't a nice easy number, such as in this example. To do it, you should read the equation as ax^2+bx+c=0, substituting the values into the equation- and remember to do it for both plus and minus! To factorise, you will need put the equation in the form (x+z)(x+t)=0. To do this, you work out the factors both of one (as there is only 1 x^2) and 15 which will add up to -8 to get you your z and t values.

JG
Answered by Jane G. Maths tutor

3232 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand the brackets? (x+4)(2x-3)


A cycle race is 3069.25 miles. Juan travels at a speed of 15.12 miles per hour. He cycles for 8 hours a day. Estimate how many days Juan will take to complete the race.


Solve the simultaneous equations; 2x + y = 18; x + 3y = 19.


Circle the number that is closest in value to (1.1)/(0.0204) [From selection of 5, 6, 50, 60] [Edit of 2018 Paper 1 Q4]


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning