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differentiate: y^2 + 3xy + x + y = 8

dy/dx = 3x+1/ -2y-3x-1

Answered by Gabrielle F. • Maths tutor

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The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).

f(x) = 2 / (x^2 + 2). Find g, the inverse of f.

Integrate the function f(x)=3^x+2 with respect to x

Integrate by parts x2^x

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