f(x) = x^2 + 4x − 6 f(x) can be written in the form (x + m)^2 + n. Find the value of m and the value of n.

Because we know (x+m)^2 expanded will provide x^2+2mx+m^2 and we have the extra addition of a value named n we can strictly focus on ensuring the expansion yields x^2+4x and deal with the -6 value by using n. Thus, by putting m as 2 we get x^2+4x+4, and following through to achieve -6 instead of 4, we put n as -10, and so we get the desired answer.

Answered by Majed G. Maths tutor

9430 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How to apply the quadratic equation


Find the opposite length of the triangle with hypotenuse length 5 and adjacent length 4.


Why do the denominators have to be equal when adding fractions, but not when multiplying them?


4x^2+5x+2=10


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences