What is the area of triangle ABC where AB = 5 cm, BC = 12 cm and angle ABC = 50 degrees?

To find the area of a triangle where the length of the base and perpendicular heights are not known, use the sine rule to find the area. This is: Area = 0.5 x a x b x sin(angle between lengths a and b) Hence for the above numbers, area = 0.5 x 5 cm x 12 cm x sin(50 degrees) = 23 sq. cm (put numbers into calculator)

AS

Related Maths GCSE answers

All answers ▸

Simplify: 2x + 6y + 2y - x


Find x and y of these two equations: 2x - 3y = 13 and 3x + y = 3


How do I use trigonometric ratios to work out lengths in right-angled triangles?


Find a solution for the following simultaneous equations: 2x+y=5 and 2x-5y=2