A baby in a bouncer bounces up and down with a period of 1.2s and amplitude of 90mm. Calculate the baby's maximum velocity.

Relevant equations: 1) frequency = 1/ time period; 2) v(max) = Amplitude*(2pifrequency)

First, we need to calculate the frequency of the baby's oscillation. That is, the number of times, per second, that the baby moves up, then down, and back to their original position. We do this by substituting the values into equation 1. Then, we use that value in equation 2 to find the speed at which the baby moves fastest - their maximum velocity. They will travel at this speed when moving through their original position when their acceleration is zero.

SH
Answered by Sam H. Physics tutor

3906 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Calculate the distance travelled by the ball traveling at 3m/s for 60 seconds


Give one advantage and one disadvantage of using nuclear power stations rather than gas-fired power stations to generate electricity. (2 Marks)


What is terminal velocity?


What is meant by terminal velocity?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning