A baby in a bouncer bounces up and down with a period of 1.2s and amplitude of 90mm. Calculate the baby's maximum velocity.

Relevant equations: 1) frequency = 1/ time period; 2) v(max) = Amplitude*(2pifrequency)

First, we need to calculate the frequency of the baby's oscillation. That is, the number of times, per second, that the baby moves up, then down, and back to their original position. We do this by substituting the values into equation 1. Then, we use that value in equation 2 to find the speed at which the baby moves fastest - their maximum velocity. They will travel at this speed when moving through their original position when their acceleration is zero.

SH
Answered by Sam H. Physics tutor

3849 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is electrical current?


A motor does 4.8kJ of work in 2 minutes. What is its power output?


How do you improve measurements and reduce error in a physics lab experiment?


Which renewable energy methods are the best?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning