Differentiate y=ln(2x^2) with respect to x
Making a substitution for u = 2x^2 Now y = ln(u) dy/dx = du/dx * dy/du du/dx = 4x dy/du = 1/u dy/dx = 4x/u Then substitute 2x^2 back in as u The final answer is 4x/(2x^2) Which can be simplified by dividing through by 2 and x to get 2/x
CG
Related Maths A Level answers
All answers ▸The rate of decay of the mass is modelled by the differential equation dx/dt = -(5/2)x. Given that x = 60 when t = 0, solve the quation for x in terms of t.
The line AB has equation 5x + 3y + 3 = 0. The point with coordinates (2k + 3, 4 -3k) lies on the line AB. How do you find the value of k.
The Curve C shows parametric equations x = 4tant and y = 5((3)^1/2)(sin2t) , Point P is located at (4(3)^1/2, 15/2) Find dy/dx at P.
How do I show two lines are skew?