How do you intergrate ln(x)?
There's a nice trick here you can do, treat the equation as 1*ln(x) then intergrate by parts.
Differentiating ln(x) gives 1/x, while intergrating 1 gives x
So your left with a much easier intergration
xln(x)-(Intergral sign)x 1/x dx
which is simply x*ln(x)-x
OM
Related Maths A Level answers
All answers ▸I'm supposed to calculate the differential of f(x)= sin(x)*ln(x)*(x-4)^2 using the product rule. I know what the product rule is but I can't split this into two bits that are easy to differentiate. How do I do it?
differentiate: y=[xcos(x^3)]/[(x^4 + 1)^3] with respect to x
integrate by parts ln(x)/x^3
Differentiate Y = 4X/(X^2+5) and give dy/dx in its simplest form