Expand and simplify the following equation: 6(x-3) - 4(x-5) = 0

Start off by dealing with the brackets by expanding. The brackets around a part of the equation imply that the entire content of the brackets will be affected by the factor outside of the brackets, in this case multiplied by 6 for the first bracket, and multiplied by -4 for the second. The first bracket gives us "6x - 18" and the second, "-4x+20". Since we included the subtraction sign in the factor which was affecting our bracket, we can just join the two sets of terms together in one expression; "6x-18-4x+20". Simplify and form a final expression. Rearrange the terms so the "x"s are together and the integers are together also, 6x-4x+20-18 = 2x + 2 (END ANSWER)

Answered by Sophia H. Maths tutor

10512 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the square of an odd number is always 1 more than a multiple of 4.


Solve the simultaneous equations: y=x^2+4x-2, y=x+2


A gym has 275 members. 40% are bronze members. 28% are silver members. The rest are gold members. Work out the number of gold members.


Solve the simultaneous equations 2x + 3y = 4, 3x + 6y = 3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences