The curve C has equation x^2 + 2xy + 3y^2 = 4. Find dy/dx.

Here, we have to use implicit differentiation, along with the product rule. Remember that the product rule is (vu)' = vu'+uv'. Moving through the equation we have: x^2+2xy+3y^2 = 4 ==> 2x +2y + 2x*(dy/dx) + 6y*(dy/dx) = 0, remembering the rules of implicit differentiation. Factorising out dy/dx = -(2x+2y)/(2x+6y).

CB

Related Maths A Level answers

All answers ▸

Two particles, A and B, are moving directly towards each other on a straight line with speeds of 6 m/s and 8 m/s respectively. The mass of A is 3 kg, and the mass of B is 2 kg. They collide to form a single particle of speed "v" m/s. Find v.


Find the equation of the tangent at x=1 for the curve y=(4x^2+1)^3


If y=cos(3x)cosec(4x), find dy/dx.


Find the integral of xcosx(dx)