The braking distance of a road train travelling at 15m/s is 70m. Assuming that the same braking force is applied at all speeds, show that the braking distance of a road train when travelling at 25m/s is about 190m.

Energy = force x distance and Energy = 0.5 x mass x velocity squared

Hence, force = (0.5 x mass x velocity squared) / distance --- (equation 1) This applies for both situation A and B, and given that force is stated to be the same in each case, and mass is the same, we can equate eqn 1 for each.

Hence, (0.5 x mass x velocity(A) squared) / distance(A) = (0.5 x mass x velocity(B) squared) / distance(B)

and so distance(B) = (velocity(B) squared x distance(A)) / (velocity(A) squared) = (25^2 x 70) / 15^2 = 194m

JJ
Answered by Jack J. Physics tutor

10354 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

2 Capacitors (c1 = 500mf) and (c2=300mf), are connected in parallel to a 10v d.c supply. Calculate the total capacitance of the circuit, and hence the total energy stored in the capacitors.


Why does a body engaged in uniform circular motion do no work?


Describe how a capacitor works.


Two forces of 4N and 10N act on a body. Which of the following could not be the resultant magnitude? (14N, 7N, 6N, 3N)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning