The braking distance of a road train travelling at 15m/s is 70m. Assuming that the same braking force is applied at all speeds, show that the braking distance of a road train when travelling at 25m/s is about 190m.

Energy = force x distance and Energy = 0.5 x mass x velocity squared

Hence, force = (0.5 x mass x velocity squared) / distance --- (equation 1) This applies for both situation A and B, and given that force is stated to be the same in each case, and mass is the same, we can equate eqn 1 for each.

Hence, (0.5 x mass x velocity(A) squared) / distance(A) = (0.5 x mass x velocity(B) squared) / distance(B)

and so distance(B) = (velocity(B) squared x distance(A)) / (velocity(A) squared) = (25^2 x 70) / 15^2 = 194m

JJ
Answered by Jack J. Physics tutor

10350 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.


In the Photoelectric Effect, what is mean by 'threshold frequency' and how does the magnitude a photons frequency effect the electron it is absorbed by?


The friction coefficient of Formula 1 car tyres are around 1.7 in dry weather. Assuming sufficient power from the engine, calculate the theoretical best 0-100 km/h acceleration time in seconds. (neglect downforce, g=9.81m/s^2)


Is a photon a wave or a particle??


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning