Solve (z-i)+(z+i)+(z-1)+(z-1)

Since we are dealing with complex numbers and taking its modulus, we can rewrite (z-i)=((-1)(i-z))=(i-z) doing the same for (z-1)=(1-z) we get (i-z)+(z+i)+(1-z)+(z-1)=(i+i+z-z+1+1+z-z) =(2i+2)=4 as we are taking its modulus.

Related Further Mathematics A Level answers

All answers ▸

By using an integrating factor, solve the differential equation dy/dx + 4y/x = 6x^-3 (6 marks)


In statistics, what is the benefit of taking a sample survey rather than a census?


How do I find the asymptotes of a curve?


Give the general solution to y'' - 3y' + 2y = 4x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences