Susan is researching the population growth of a city. She proposes that x, the number of people in the city, t years after 2017 is given by x=250,000e^(0.012t) A.population in 2017 B.population in 2020 C.During which year would the population have doubled

A. t=0 ; x=250,000 B. 2020, so t=3. plug in to equation > x=250,000e^(0.012)3 = 259,163 (people so cannot round up) C. Population to double so 500,000 = 250,000e^(0.012)t -> 1/0.012(ln2) = t t= 57.7 years ; 2017 + 57 = 2074 when population doubles

JG
Answered by James G. Maths tutor

4513 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve is defined for x > 0. The gradient of the curve at the point (x,y) is given by dy/dx = x^(3/2)-2x. Show that this curve has a minimum point and find it.


Show that, for all a, b and c, a^log_b (c) = c^log_b (a).


(a) Express (1+4*sqrt(7))/(5+2*sqrt(7)) in the form a+b*sqrt(7), where a and b are integers. (b) Then solve the equation x*(9*sqrt(5)-2*sqrt(45))=sqrt(80).


integrate x^2 + 3x + 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning