Solve the following simultaneous equations to obtain values for x and y: 2x + y = 7 & 3x - y = 8.

Label your equations 1 and 2 respectively. Make y the subject of equation 2 by taking away 3x from both sides and multiplying both sides by -1, to get y = 3x - 8. Now substitute this into equation 1 (i.e. replace the 'y' in equation 1 with '3x - 8'), giving 2x + (3x - 8) = 7. By grouping like terms together and adding 8 to both sides we get 5x = 15. Now to obtain our value of x simply divide both sides by 5, hence x = 3. Now use this value of x to find y. Substitute x = 3 into equation 2. So 3(3) - y = 8. This gives 9 - y = 8. By subtracting 9 from both sides and multiplying both sides by -1, we can get our value of y, giving y = 1. 

PM
Answered by Pratham M. Maths tutor

3688 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 495 coins in a bottle. 1/3 of the coins are £1 coins. 124 of the coins are 50p coins. The rest of the coins are 20p coins. Work out the total value of the 495 coins


The Diagram shows the Triangle PQR. PQ = x cm. PR = 2x cm. Angle QP^R = 30 degrees. The area of the triangle PQR = A cm^2. Show that x = (Squared Root){2A


Simplify 2^11 x 8


Using Algebra show that part of the line 3x + 4y = 0 is a diameter of the circle with equation (x^2) + (y^2) = 25


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning