Find the values of k for which the equation (2k-3)x^2 - kx + (k-1) = 0
A quadratic equation has two equal roots when its discriminant is equal to 0. Calculating the discriminant of the given equation: D = k2 - 4(k-1)(2k-3) = k2 - 8k2+20k-12 = -7k2+20k-12=0 Solving this equation for k: 7k2-20k+12=0 D = 100-84 = 16 k1,2=(10+-4)/7 => k = 6/7, k=2
KP
Related Maths A Level answers
All answers ▸What is the normal distribution and how do I use it?
The curve C has equation y = 3x^4 – 8x^3 – 3 (a) Find (i) dy/dx (ii) d^2y/dx^2 (3 marks) (b) Verify that C has a stationary point when x = 2 (2marks) (c) Determine the nature of this stationary point, giving a reason for your answer. (2)
Find the derivative of y = 3x^4 - 10x^2+7x
How do you differentiate y=x^x?