Find the values of k for which the equation (2k-3)x^2 - kx + (k-1) = 0
A quadratic equation has two equal roots when its discriminant is equal to 0. Calculating the discriminant of the given equation: D = k2 - 4(k-1)(2k-3) = k2 - 8k2+20k-12 = -7k2+20k-12=0 Solving this equation for k: 7k2-20k+12=0 D = 100-84 = 16 k1,2=(10+-4)/7 => k = 6/7, k=2
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