Prove that (4x–5)^2 – 5x(3x – 8) is positive for all values of x.

To begin we need to simplify the expression. First we multiply out (4x–5)^2 to get 16x2+40x+25 and then we multiply out 5x(3x – 8) to get 15x2-40x. This makes the whole expression 16x2+40x+25-(15x2-40x), which equals 16x2+40x+25-15x2+40x. This simplifies to x2+25. We know that x2 is positive for all values of x, and so x2+25 must also be positive for all values of x.

Answered by Hannah W. Maths tutor

8953 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is completing the square?


Find the roots of the following equation 2x^2-11x+14=0


Solve the simultaneous equations: 3x + y = -4 and 3x - 4y = 6


How do I solve inequalities when they're not linear?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences