solve this equation: 4(x-5)=x+7
Firstly, I will provide a 'mark scheme' type answer.
Then there is a full explanation available underneath. 4 (x-5)=x+7. 4x-20=x+7. 3x=27. x=9. A full explanation: 4(x-5)=x+7 (expand the equation on the left. TOP TIP: pretend there is a multiplication sign between 4 and the phrase of (x-5) :) Therefore, mutliply x by 4 and then multiply 4 and -5.) 4x-20=x+7. (Take x away from both sides). Therefore you will end up with: 4x-x-20=7. THEREFORE 3x-20=7. (Add 20 to both sides) 3x=7+20 3x=27. (Divide by 3 for both sides) x= 27/3 x=9
AM
Related Maths GCSE answers
All answers ▸prove that any odd number squared is one more than a multiple of four.
ABC is an isosceles triangle such that AB = AC A has coordinates (4, 37) B and C lie on the line with equation 3y = 2x + 12 Find an equation of the line of symmetry of triangle ABC. Give your answer in the form px + qy = r where p, q and are integers (5
ABCD is a square of side 10 cm. Each side of the square is a tangent to the circle. Work out the total area of the shaded regions in terms of . Give your answer in its simplest form.
Find max point of y=-x^2-5x-10