Give the possible values of x when 2x^2-x-6=0

first of all the equation needs to be written in the form (ax+b)(x+c) 

because 2 can only be made by multiplying 2 and 1 we know that a=2 so (2x+b)(x+c)

-6 can be made by multiplying 2 and -3, -2 and 3, -6 and 1 or 6 and -1

the easiest way to work this out is trial and error to make sure we can get -x in the middle

so from this we can write it as (2x+3)(x-2)=0

because 0 multiplied by anything =0 we know that the contents of each bracket can =0: 2x+3=0 and x-2=0

by rearranging these equations to solve for x we can work out that the answer to this question is x=2 or x=-3/2

Answered by Nina S. Maths tutor

3375 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

x : y = 11 : 3 x + y = 140 Find x and y


Solve: 5x - 2 > 3x + 11


I struggle with the following type of question: "The first four terms of an arithmetic sequence are 5, 9, 13, 17. Write down an expression, in terms of n, for the nth term in the sequence." How should I approach this?


Aled has three concrete slabs. Two of the slabs are square, with each side of length x metres. The third slab is rectangular and measures 1 metre by (x +1) metres. The three concrete slabs cover an area of 7m^2. Show that 2x^2 + x – 6 = 0. Find x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences