Differentiate y=(x^2+1)(e^-x)

Here, we're using the product rule (and the chain rule for the e-x): y=(x2+1)(e-x) dy/dx=(2x)(e-x)+(x2+1)(-1)(e-x) Then we simplify to get: dy/dx=(e-x)(2x-x2-1)

RD
Answered by Rishav D. Maths tutor

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