Differentiate y = lnx + 4x^2 + 3e^4x with respect to x

lnx differentiates to 1/x

4x^2 differentiates to 8x

3e^4x differentiates to 12e^4x

therefore the answer is: 1/x + 8x + 12e^4x

Answered by Dhylon S. Maths tutor

3582 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the tangent to the curve y = (5x+4)/(3x-8) at the point (2, -7).


complete the square of x^2 + 2x - 6


a) Simplify 2ln(2x+1) - 10 = 0 b) Simplify 3^(x)*e^(4x) = e^(7)


integrate ln(x) using integration by parts


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences