Differentiate y=x^3*(x^2+1)

As this is a product of two functions it is necessary to use the product rule for differentiation. Therefore one of the functions must labeled v and the other u. i.e. u=x^3 and v=(x^2+1). It is then necessary to differentiate each of those functions seperately so that du/dx=3x^2 and dv/dx=2x. The final step is to multiply v by du/dx and multiply v by du/dx then add the two together as follows: dy/dx=2x^4+3x^2*(x^2+1)

BJ
Answered by Bevan J. Maths tutor

3446 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)


Express (3x^2 - 3x - 2)/(x-1)(x-2) in partial fractions


Given that y=4x^3-(5/x^2) what is dy/dx in it's simplest form?


How can I find all the solutions to cos(3x) = sqrt(2)/2 for 0<=x<=2pi ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning