The first step for this question is to find out how much energy is absorbed by the electron above its work function. This is found with the kinetic energy equation: K.E.=1/2mv^2 The mass of an electron is 9.1x10^-31. Using this in the above equation finds the kinetic energy to be: K.E=0.59.1x10^-31(5x10^5)^2= 1.14x10^-19 J The kinetic energy is the energy above the work function. The energy provided from the photon of light is calculated with: E=(h*c)/L where E is the energy, h is the planck constant, c is the speed of light, and L is the wavelength.Inputting the correct values into the above equation gives: E=6.63 x 10^-34 x 3.0 x 10^8 / 5.9 x 10^-7= 3.37x10-19 J Finally, the work function can be found by subtracting the kinetic energy from the energy provided by the photon to give: W.F.= (3.37-1.14)x10^-19= 2.23x10^-19 J