The mercury atoms in a fluorescent tube are excited and then emit photons in the ultraviolet region of the electromagnetic spectrum. Explain (i) how the mercury atoms become excited and (ii) how the excited atoms emit photons.

(i) As they pass through the fluorescent tube, they collide with the mercury atoms within it and this collision transfers energy to the atom. This energy transfer allows the atom's orbiting electrons to move to a higher energy state thus exciting the atom. (ii) Shortly after the collision, the atom proceeds to de-excite. The higher-energy electron returns to the ground state and a photon of equal energy to the difference in energy levels the electron travels through is emitted to conserve energy.

EH
Answered by Evan H. Physics tutor

27192 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Explain, using appropriate laws of motion, why the air exerts a force on the engine in the forward direction.


A pendulum of mass m is released from height h with a speed v at the bottom of its swing. a) What is the gravitational potential energy at height h and the kinetic energy at the bottom of its swing? b) Use conservation of energy to define the speed v.


Describe and explain the photoelectric effect in terms of photons interacting with the surface of a metal.


Why does Lenz's law have a minus sign?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning