The mercury atoms in a fluorescent tube are excited and then emit photons in the ultraviolet region of the electromagnetic spectrum. Explain (i) how the mercury atoms become excited and (ii) how the excited atoms emit photons.

(i) As they pass through the fluorescent tube, they collide with the mercury atoms within it and this collision transfers energy to the atom. This energy transfer allows the atom's orbiting electrons to move to a higher energy state thus exciting the atom. (ii) Shortly after the collision, the atom proceeds to de-excite. The higher-energy electron returns to the ground state and a photon of equal energy to the difference in energy levels the electron travels through is emitted to conserve energy.

EH
Answered by Evan H. Physics tutor

27385 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

State and derive Kepler's third law


How can an object be accelerating when it's velocity is constant, and how does centripetal acceleration work.


An infared wave has a wavelength of 1.5 x10^–6 m. The speed of this wave is 2.2 × 10^8 m/s. Calculate the frequency of the wave. Give your answer in standard form and to 2 significant figures.


Calculate the time taken for 1000L of water at rtp to be heated to 40degrees celsius using a 40kW heater


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning