The curve y = 2x^3 - ax^2 + 8x + 2 passes through the point B where x=4. Given that B is a stationary point of the curve, find the value of the constant a.

As B is a stationary point, the value of dy/dx at this point must be equal to 0. Differentiating y gives this to be dy/dx = 6x2-2ax+8. At point Bx=4. This gives the relation 104=8a and thus gives a=13.

Answered by Evan H. Maths tutor

8060 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

a) Differentiate and b) integrate f(x)=xcos(2x) with respect to x


Integrate 4x^3 with respect to x


integrate (4cos^4 x -4cos^2x+1)^1/2


Given y = 3x^(1/2) - 6x + 4, x > 0. 1) Find the integral of y with respect to x, simplifying each term. 2) Differentiate the equation for y with respect to x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences