Find the vertex coordinates of parabola y = 2x^2 - 4x + 1
In this exercise I have to find the coordinates of the vertex of the parabola. Given the general equation y= ax^2 + bx + c , the value of a is 2, the value of b is -4 and the value of c is 1.
In order to compute the x-coordinate, I apply the formula –b/2a and, by substituting the values written before, I have that Vx = -(-4)/(2*2) = 4/4 = 1.
For the y-coordinate, I apply the formula –Δ/4a, where Δ = b^2 – 4ac. By substituting the parameters value into Δ, I obtain Δ = (-4)^2 – 421 = 16 -8 = 8. By plugging it into the general formule, I have Vy = - 8/(4*2) = - 8/8 = - 1. The vertex coordinates are thus (1; - 1).
MB
Related Maths A Level answers
All answers ▸Find the equation of the tangent to the curve y = 4x^2 (x+3)^5 at the point (-1, 128).
A particle of weight 15N is resting on a plane inclined at an angle of 30°. Find : a) the normal force exerted on the particle, b) the coefficient of friction between the particle and the plane, providing it is in limiting equilibrium
Integrate tan(x)^2 with respect to x
The quadratic equation 2x^2+8x+1=0 has roots a and b. Write down the value of a+b and ab and a^2+b^2.