How do you solve the following simultaneous equations? Equation 1: 2x + 3y = 13 Equation 2: 3x - y = 3

There are various ways to solve simultaneous equations. The two easiest are by elimiation and by substitution. By Elimation When solving by elimination you want to ensure that you only have one variable (x or y) in the remaining equation. In order to do this you want to have the coefficient (number in front of the variable) equal for one of the variables across the two equations. This requires some manoevering. Equation 2: 3x - y = 3 -3Equation 2 = -9x + 3y = -9 Then you are able to subtract one from the other Equation 1 --3Equation 2 = Equation 1 + 3Equation 2 = 2x + 3y = 13   + 9x - 3y = 9 = 11x = 22 x = 2 if x = 2, then 22 + 3y = 13 so 3y = 9 so y = 3 By Substitution This method means that one variable is rearranged to be the subject of one equation, then is substituted into the other, like seen below. Equation 2: 3x - y = 3 3x = y + 3 y = 3x - 3 Equation 1: 2x + 3y = 13 2x + 3(3x - 3) = 13 2x + 9x - 9 = 13 11x = 22 so x = 2 if x = 2, then 2*2 + 3y = 13 so 3y = 9 so y = 3

LS
Answered by Luke S. Maths tutor

8288 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

ABC are points on a circle, centre O. AO=9cm, OC=9cm and AC=15cm. Find the angle ABC.


Solve n^2 – n – 90 = 0 to find value of n


How to Solve: (11 − w)/4 = 1 + w


The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences