Part I (4 marks) a) C6H12O6 + 6O2 -> 6CO2 + 6H2O b) C6H12O6 + 3O2 -> 6CO + 6H2O Part II (2 marks) Equation (a) could be carried out in an open vessel where there is an excess of oxygen, whereas equation (b) would be carried out within a closed vessel. The reaction being carried out in a closed vessel means that the supply of oxygen is less and thus carbon monoxide is produced rather than carbon dioxide.