A block of ice slides down the full height from one side of a 1m high bowl and up the other side. Assuming frictionless motion and taking g as 9.81ms-2, find the speed of the block at the bottom of the bowl and the height it reaches on the the other side.
Using the law of conservation of energy, the potential energy of the block is transferred to kinetic energy as it slides down. KE [0.5mv2] = PE [mgh], v = √2gh v = √29.811 = 4.43 ms-1 The block's KE will be transferred back to PE as it rises so it will slide up to the same height it slid down from - 1m.
OS
Related Physics A Level answers
All answers ▸A basketball player throws his ball vertically upwards with an initial speed of v=40 m/s. Ignore air resistance. What is the speed of the ball at half of the maximum height?
You have a layer of glass with a refractive index of 1.5 and the glass is surrounded by air. A light ray shines into the glass and Total Internal Reflection occurs at the glass-air boundary. What is the critical angle?
How did rutherford's gold leaf experiment prove the existence of the nucleus?
A pendulum of mass m is released from height h with a speed v at the bottom of its swing. a) What is the gravitational potential energy at height h and the kinetic energy at the bottom of its swing? b) Use conservation of energy to define the speed v.