A block of ice slides down the full height from one side of a 1m high bowl and up the other side. Assuming frictionless motion and taking g as 9.81ms-2, find the speed of the block at the bottom of the bowl and the height it reaches on the the other side.

Using the law of conservation of energy, the potential energy of the block is transferred to kinetic energy as it slides down. KE [0.5mv²] = PE [mgh], v = √2gh v = √29.811 = 4.43 ms^-1 The block's KE will be transferred back to PE as it rises so it will slide up to the same height it slid down from - 1m.